Answer: Mn2+(aq)→MnO2(s)
Explanation: Balancing O in an aqueous medium, we get: Mn2+(aq)+2H2O(l)→MnO2(s)
Balancing H in an acidic medium, we get: Mn2(aq)+2H2O(l)→MnO2(s)+4H+(aq)
Balancing charge, we get: Mn2+(aq)+2H2O(l)→MnO2(s)+4H+(aq)+2e−
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