Question

the volume of a sample of hydrogen gas was decreased from 11.34 l to 4.63 l at constant temperature. if the final pressure exerted by the hydrogen gas sample was 6.64 atm, what pressure did the hydrogen gas exert before its volume was decreased?

Answer 1

p=2.74 atm

Step-by-step explanation:

According to Boyle's Law, at a constant temperature, a gas' pressure is inversely proportional to volume. This relationship is used to establish the following equation:

`p_1v_1=p_2v_2`

For this problem, let

`v_1=11.24l\\v_2=4.63l\\p_2=6.64atm`

So,

`p_1(11.24l)=(4.63l)(6.64atm)\\p_1(11.24l)=30.74l*atm\\(p_1(11.24l))/(11.24l)=(30.74l*atm)/(11.24l)\\p_1=2.74atm`

This answer makes sense according to Boyle's Law. As the volume decreases, pressure must increase. Since the initial volume is higher, the initial pressure should be lower.