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How many grams of oxygen O2 are in 54L at STP? hint all gases 22.4 L per mole at stp)

a. 62.2g
b.77.1g
c. 19.7g

User Selvaraj
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1 Answer

5 votes

Answer:

hope this answer will help you

Step-by-step explanation:

we can simply do this by unitary method

22.4L is requires or 1 mole of oxygen gas

54L requires 1/22.4×54 = 2.41 moles

we know that no. of moles =mass/mol.mass

in order to get mass we multiply moles by mol. mass

2.41×32=77.1g

so, the correct option is

User Marek Blotny
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