Answer: 4
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Reason:
Let
- f(x) = 4x
- h(x) = 2x^4-2x^2+4
If we want to evaluate this limit

Then we need to evaluate these limits as well:

This is because g(x) is bound entirely by these lower and upper functions. Refer to the squeeze theorem for more information.
To evaluate those two other limits, we simply plug x = 1 into each function.
You should find that:
Each function results in 4 when x = 1. This then extends to the idea that f(x) approaches 4 when x approaches 1; similarly, h(x) approaches 4 when x approaches 1.
Therefore, g(x) must approach this same y value to be contained within both these boundaries. These two boundaries squeeze or pinch g(x) into one possible option here.