Question

How many L of 0.8 M Hcl are required to neutralize 3.5 L of 1.2 M KOH?

a. 19.4L
b.4.1L
c. 3.3L
d.5.3L

Answer 1

hope this answer will help you.

Step-by-step explanation:

in order to find the volume of HCl we use formula C1V1=C2V2

where C1=concentration of HCl and V1 is the volume of HCl while C2 is concentration of KOH and V2 is the volume me of KOH

C2V2/C1=V1

1.2×3.5/0.8= 5.25L

so, the volume of HCl is 5.25L which 5.3 after round off the figure

the correct option is "d"