To find the minimum value of the expression y=15(x-25)^2+130, we can set the derivative of the expression equal to 0 and solve for x. This will give us the value of x that corresponds to the minimum value of y.
The derivative of the expression is given by:
dy/dx = 30(x-25)
Setting this equal to 0, we get:
0 = 30(x-25)
Solving for x, we get:
x = 25
Substituting this value into the original expression for y, we get:
y = 15(25-25)^2+130 = 130
Therefore, the minimum value of y is 130, which is achieved when x=25.