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A rectangle’s length is 2a and it’s area is 2a^2+12ab. If the width of the rectangle is written in the form Pa+Qb what are P and Q?
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A rectangle’s length is 2a and it’s area is 2a^2+12ab. If the width of the rectangle is written in the form Pa+Qb what are P and Q?

User Alex Punnen
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1 Answer

4 votes

Answer: Answer in explanation

Explanation:

P = 1 and Q = 6

divide the (2a^2+12ab) by 2a

User Vlax
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