Answer:
Explanation:
f(x)=x-2 sin x
f'(x)=1-2 cos x
f'(x)=0 gives 1-2 cos x=0
cos x=1/2=cos 60,cos (360-60)
x=60,300
f"(x)=2sin x
at x=60
f"(x)=sin 60=3/2>0
so there is minima.
at x=300
f"(x)=sin 300=sin (360-60)=-sin 60=-3/2<0
so there is maxima .
generalizing
x=300+360n
where n is an integer.
and there is relative minima at x=60+360n where n is an integer.