Answer:
Option A
Explanation:
The complete question is
The pentagon ABCDE is graphed on a coordinate plane with vertices A(0, 0), B(3, 5), C(3, 8), D(8, 5), and E(8, 0). What is the pentagon's perimeter?
Solution -
We will find the length of all the sides of pentagon and then add them
Length of AB = Sqrt ((3-0)^2+(5-0)^2) = Square root of 9+25 = 5.83
Length of BC = Sqrt ((3-3)^2+(8-5)^2) = Square root of 9 = 3
Length of CD = Sqrt ((8-3)^2+(5-8)^2) = Square root of 5^2+-3^2
= 5.83
Length of DE = Sqrt ((8-8)^2+(0-5)^2) = Square root of 25 = 5
Length of EA = Sqrt ((8-0)^2+(0-0)^2) = Square root of 64= 8
Perimeter=8+5+5.83+5.83+3= 27.66 units =27.66 units
Option A