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The distance ab =?
round to the nearest tenth​

The distance ab =? round to the nearest tenth​-example-1

2 Answers

3 votes

Answer:

D≈2.8

Explanation:

A(-3,1) and B(-1,-1)

d=square root of [(x2-x1)^2+(y2-y1)^2]

d=square root of [(-1+3)^2+(-1-1)^2]

d=square root of [8]

d≈2.8

User JCCyC
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4.2k points
3 votes

Check the picture below.


~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ AB=√((~~-1 - (-3)~~)^2 + (~~-1 - 1~~)^2) \implies AB=√((-1 +3)^2 + (-1 -1)^2) \\\\\\ AB=√(( 2 )^2 + ( -2 )^2) \implies AB=√( 4 + 4 ) \implies AB=√( 8 )\implies AB\approx 2.8

The distance ab =? round to the nearest tenth​-example-1
User Payton Byrd
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4.6k points