The area of the region between the two curves by integrating over the y-axis, x = y² and x = 9 is 18 square units.
Total Area inclosed between line and Curve:
The area where the "area under the curve" is common to both the straight line and the given curve is called the bounding area. Therefore, the area common to both can be found by subtracting the area under line T from the area under curve C. The x constraint for computing the area under the curve can be found by solving the system of equations for the coordinates of the intersection of the line and the curve.
We have given the curve , x = y² and line x = 9 and bounded region is A in above graph of x = y² and line x = 9.
Now, we determine the intersection points of curve and line,
put x = 9 in curve equation we get,
y² = 9 => y = +-√9
= + 3 or -3
Total area bounded by curve and line, A = integration of curve over y from y = -3 to y= 3
= ₋₃∫³x dy = ₋₃∫³y² dy = ₋₃[ y³/3]³
= [ (3)³/3 - (-3)³/3]
= 9 + 9 = 18
Hence, the required area is 18 square unit.
Complete question:
determine the area (in units2) of the region between the two curves by integrating over the y-axis. x = y² , x = 9