Question

How many mL of 0.500 M Nal would be required to make a 0.0410 M

solution of Nal when diluted to 275.0 mL with water?

Answer 1

V1 M1 = V2M2
(V1 ml)(0.500 M) = (275 ml)(0.0350 M)
V1 = (275 ml)(0.0350 M) / 0.500 M
V1 = 19.25 mls = 19.3 mls (3 sif. figs.) would be required