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The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?

Question 4 options:



2w + 2 • (5w) ≤ 96




2w + 2 • (5w) ≥ 96




2w + 2 • (5w) < 96




2w + 2 • (5w) > 96

1 Answer

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Answer:

  • A) 2w + 2 • (5w) ≤ 96

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Given:

  • Width is w,
  • Length is l = 5w.

Perimeter is:

  • P = 2(l + w)

or

  • 2w + 2(5w)

The perimeter is at most 96 cm (not greater than):

  • 2w + 2(5w) ≤ 96

The matching choice is A.

User Garu
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