Question

A straight line passing through A(3,2) and B(5,y) has gradient -2. find the value of y​

Answer 1

y=-2

Explanation:

For a line containing the points (X1,Y1) and (X2,Y2), the gradient/slope is equal to (Y2-Y1)/(X2-X1).

Therefore for a line with gradient -2 and points (3,2) and (5,y), we can say:

-2=(y-2)/(5-3)

-2(2)=y-2

y=-4+2

y=-2

Answer 2

Explanation:

`gradient \: = \: (y2 - y1)/(x2 - x1)`

y2 = y , x2 = 5

y1 = 2 , x1 = 3

`- 2 \: = \: (y - 2)/(5 - 3)`

-4 = y-2 ==> y = -2