Question

A 295 g aluminum engine part at an initial temperature if 13.00 degrees Celsius absorbs 75.0 kJ of heat. What is the final temperature of the part (c of AL - 0.900 J/gK)?

Answer 1

The final temperature of the aluminum engine part after absorbing 75.0 kJ of heat is 295.67°C, calculated using the specific heat capacity of aluminum and the mass of the part.

Step-by-step explanation:

To find the final temperature of a 295 g aluminum engine part after absorbing 75.0 kJ of heat, we can use the heat transfer equation Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Using the specific heat capacity of aluminum, which is 0.900 J/g°C, and the mass of the part (295 g), we can rearrange the equation to solve for the change in temperature: ΔT = Q / (mc).

First, convert the given heat from kJ to J: 75.0 kJ = 75,000 J. Then use the equation ΔT = Q / (mc) to calculate the change in temperature.

ΔT = 75,000 J / (295 g × 0.900 J/g°C) = 75,000 J / 265.5 J/°C ≈ 282.67°C

Now, add the change in temperature to the initial temperature to find the final temperature:

Final Temperature = Initial Temperature + ΔT = 13.00°C + 282.67°C = 295.67°C

Answer 2

Answer: 295°C


Explanation: Given data:

The mass is m=295g
The initial temperature is T1=13∘C
The absorbed heat is Q=75kJ
The specific heat of aluminum is CAl=0.9J/g∘C


The expression for the heat is written as:

Q=mCAl(T2−T1)

Here, T2is the final temperature



Substitute the known values:
75×103=295g×0.9J/g∘C(T2−13∘C)T2≈295∘C
Thus, the final temperature is 295∘C.