Question

ASAPPP! An arrow is shot into the air. A function representing the relationship between the number of

seconds it is in the air, t, and the height of the arrow in feet, h, is given by the equation below.
What is the initial height of the arrow?
h(t) = -16t^2+ 128t + 1.5

Answer 1

The initial height of the arrow is 1.5 feet above the ground.

Explanation:

Let be the height of the arrow be represented by the function
`h(t) = -16\cdot t^(2)+128\cdot t + 1.5`, where
`h(t)` is the current height of the arrow, measured in feet, and
`t`, is the time, measured in seconds.

Mathematically speaking, the initial height is the value of
`h` evaluated at
`t = 0\,s`. That is:

`h(0) = -16\cdot (0)^(2)+128\cdot (0) + 1.5`

`h(0) = 1.5\,ft`

The initial height of the arrow is 1.5 feet above the ground.