Question

A train travelling along a straight line with constant acceleration is observed to travel consecutive distances of 1km in times of 30s and 60s respectively. Find the initial velocity of the train.

Answer 1

116.7m/s

Explanation:

distance(s) = 1km = 1 × 1000m = 1000m

Time(t) = 60– 30 = 30s

initial velocity = u

acceleration (a) = 10m/s

using the formula

S = ut + ½at²

1000 = 30u + ½ × 10 × 30²

1000 = 30u + 5 × 900

1000 = 30u + 4500

30u = 4500 – 1000

30u = 3500

divide both sides by 30

u = 116.7m/s

i hope i helped