Answer:
4.2 moles of sodium cyanide (NaCN) would be needed to produce 2.1 moles of sodium sulfate (Na₂SO₄).
Step-by-step explanation:
The balanced reaction is:
H₂SO₄ + 2 NaCN → 2 HCN + Na₂SO₄
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound are necessary:
- H₂SO₄: 1 mole
- NaCN: 2 moles
- HCN: 2 moles
- Na₂SO₄: 1 mole
Then you can apply the following rule of three: if by stoichiometry to produce 1 mole of sodium sulfate 2 moles of sodium cyanide are necessary, then to produce 2.1 moles of sodium sulfate how many moles of sodium cyanide are necessary?
amount of moles of sodium cyanide= 4.2 moles
4.2 moles of sodium cyanide (NaCN) would be needed to produce 2.1 moles of sodium sulfate (Na₂SO₄).