Answer:
To solve this system of linear equations, we need to first rewrite the equations in standard form, which is the form y = mx + b. To do this, we can isolate the y-term on one side of the equation and the x-term and constant on the other side. For example, the first equation can be rewritten as follows:
-15x + 20y = 15-5
20y = 15 - 5 - 15x
y = -3/4 x + 2
Similarly, the second equation can be rewritten as follows:
0 - 18x + 24y - 18
24y = -18 - 18x
y = -3/2 x - 1
Now that the equations are in standard form, we can find the point of intersection by setting the two equations equal to each other and solving for x:
-3/4 x + 2 = -3/2 x - 1
-3/4 x + 2 + 3/2 x = -1 + 3/2 x
x = -1/6
Substituting this value of x into either equation, we can solve for y to find the point of intersection:
y = -3/4 x + 2
y = -3/4 (-1/6) + 2
y = 1/3
Therefore, the point of intersection for these two equations is (-1/6, 1/3). This means that the system of equations has exactly one solution at this point.