Question

FIND Y IN XYZ, help please

Answer 1

Given:

In triangle
`XYZ,m\angle X=90^\circ, m\angle Y=45^\circ, m\angle Z=45^\circ, XZ=y,YZ=15√(2)`.

To find:

The value of y.

Solution:

In a right angle triangle,

`\sin \theta =(Perpendicular)/(Hypotenuse)`

Using the above ratio for the triangle XYZ, we get

`\sin Y =(XZ)/(YZ)`

`\sin 45^\circ =(y)/(15√(2))`

`(1)/(√(2))=(y)/(15√(2))`

`(15√(2))/(√(2))=y`

`15=y`

Therefore, the correct option is C.