Question

SOMEONE HELP PLEASE. if f(x) is an exponetial function where f(-0.5)=18 and f(1)=52 then find the value of f(0) round to nearest hundredth

Answer 1

Explanation:

The form of a exponential function is

`y = a * {b}^(x)`

We know that

`18 = a * {b}^( - 0.5)`

`52 = a * {b}^(1)`

If we divide these two we will get

`(26)/(9) = b {}^(1.5)`

`(676)/(81) = b {}^(3)`

`\sqrt[3]{ (676)/(81) } = b`

Solving for a,

`52 = a * \sqrt[3]{ (676)/(81) }`

`a = 25.64`

f(0)=a, so

f(0)=25.64