Question

9. Given the graph of f(x), what is the quadratic equation in root form.

| 1(x)
A. f(x) = 2(x + 32)² + 1
B. f(x) = 2(x - 3)(x + 5)
C. f(x) = 2(x - 1)² - 32
D. f(x) = 2(x + 3)(x - 5)
OA
(-3,0)
OB
(1, -32)
(5,0)

Answer 1

`f(x)=2(x+3)(x-5)`

Explanation:

Using the roots,
`f(x)=a(x+3)(x-5)`.

Using the point
`(1,-32)` to solve for
`a`,

`-32=a(4)(-4) \\ \\ -32=-16a \\ \\ a=2 \\ \\ \\ \therefore f(x)=2(x+3)(x-5)`