Question

A rectangle has a length of y^2+3y+7 and a width of y-3. How much longer is the length?

Answer 1

Given:

The length of the rectangle =
`y^2+3y+7`

Width of the rectangle =
`y-3`

To find:

How much longer is the length?

Solution:

We need to find the difference between length and width of the rectangle.

`Difference=Length-Width`

`Difference=y^2+3y+7-(y-3)`

`Difference=y^2+3y+7-y+3`

`Difference=y^2+(3y-y)+(7+3)`

`Difference=y^2+2y+10`

Therefore, the length of the rectangle is
`y^2+2y+10` much longer than the width.