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7 votes
7 votes
Two numbers add to 336 and the first is 126 bigger than the five times the second. What are the two numbers?

User Wes H
by
2.5k points

2 Answers

13 votes
13 votes

Final answer:

To solve this problem, we can set up a system of equations. The first number is 301 and the second number is 35.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's call the first number 'x' and the second number 'y'. We are given two pieces of information. The first is that the two numbers add up to 336, so we have the equation:

x + y = 336

The second piece of information is that the first number is 126 bigger than five times the second number. This can be expressed as the equation:

x = 5y + 126

We can solve these two equations simultaneously to find the values of 'x' and 'y'. Rearrange the second equation to make 'y' the subject:

y = (x - 126)/5

Substitute this expression for 'y' into the first equation:

x + (x - 126)/5 = 336

Now solve for 'x' by multiplying both sides by 5 to eliminate the fraction:

5x + x - 126 = 1680

Combine like terms:

6x - 126 = 1680

Add 126 to both sides:

6x = 1806

Divide by 6 to isolate 'x':

x = 301

Now substitute this value of 'x' back into either equation to find 'y'. Using the first equation:

301 + y = 336

Subtract 301 from both sides:

y = 35

So the two numbers are 301 and 35.

User Markiv
by
2.8k points
24 votes
24 votes

Answer:

301, 35

Step-by-step explanation:

1st number = x, 2nd = y

x + y = 336

x = 126 + 5y

Then

(126 + 5y) + y = 336

6y = 336 - 126 = 210

y = 210/6 = 35

x = 126 + 5y = 126 + 5*35 = 301

Or x = 336 - 35 = 301

The two numbers are 301 and 35

User Polynomial Proton
by
2.8k points
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