Question

A gas that exerts a pressure of

15.6 psi in a container with a volume of
L will exert a pressure of
25.43 psi when transferred to a
container with a volume of 1.895 L.

Answer 1

3.089 L

Step-by-step explanation:

From the given information, provided that the no of moles and the temperature remains constant;

`P_1` = 15.6 psi

`V_1` = ???

`P_2` = 25.43 psi

`V_2` = 1.895 L

Using Boyle's law:

`P_1V_1 =P_2V_2 \\ \\ V_1 = (P_2V_2)/(P_1) \\ \\ V_1 = (25.43 * 1.895)/(15.6) \\ \\ \mathbf{ V_1 = 3.089 \ L}`