To eliminate y from the first equation, we can multiply the entire equation by -2. This will give us:
-2x - 4y = -12
Now, if we add this equation to the second equation, the y terms will cancel out, leaving us with:
-2x - 4(2) + 5z = 26
-2x + 5z = 26
Now we have two equations in two variables, x and z. We can solve this system of equations by substituting the value of y from the second equation into the first equation. This gives us:
x + 2(2) = -6
x = -10
Substituting this value of x into the second equation, we get:
-2(-10) + 5z = 26
20 + 5z = 26
5z = 6
z = 1.2
Finally, we can substitute the values of x and z back into the second equation to find the value of y:
-2(-10) - 6(1.2) + 5(1.2) = 26
20 - 7.2 + 6 = 26
12.8 = 26
This system of equations has no solution, since we have found values of x and z that make the second equation true, but substituting these values into the first equation results in a false statement. This means that there is no set of values for x, y, and z that will make all three equations true at the same time.