Which equation can you use to find the value of x? 78° 3xº (x - 2) 3x + 78 + x - 2 = 180 3x = 78 3x = 78 + x - 2 78 = x-2

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

Bart Silverstrim asked Mar 10, 2022

262,584 views

41 votes

Which equation can you use to find the value of x?

78°
3xº
(x - 2)
3x + 78 + x - 2 = 180
3x = 78
3x = 78 + x - 2
78 = x-2

Which equation can you use to find the value of x? 78° 3xº (x - 2) 3x + 78 + x - 2 = 180 3x-example-1

Mathematics
high-school

Bart Silverstrim asked Mar 10, 2022

by Bart Silverstrim

3.0k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

2 Answers

10 votes

Answer:

3x = 78 + x - 2

Explanation:

I got it right on Iready :]

Vincent Wasteels answered Mar 11, 2022

by Vincent Wasteels

2.9k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

16 votes

Answer:

3×=78+×-2

..............

Mahesh Jadhav answered Mar 14, 2022

by Mahesh Jadhav

2.3k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

2 Answers

0 Comments

Your comment on this answer:

0 Comments

Your comment on this answer:

Other Questions