Answer:
As the calculated z does not fall in the critical region we fail to reject H0 and conclude that there is sufficient evidence that the average past-due amount for customers who have been called previously about their bills is now no larger than $23.
Explanation:
As the standard deviation for the past due amounts is 63
The sample size n= 67
1) Formulate the null and alternate hypothesis
H0: u ≤ 23 against the claim Ha: u > 23
2) The test statistics is
Z= x- u / σ/ √n
z= 20- 23/ 63/ √67
z= 0.00581
z= 0.006
3) The significance level ∝= 0.1
4) The critical value for ∝= 0.1 is Z > ±2.33
5) As the calculated z does not fall in the critical region we fail to reject H0 and conclude that there is sufficient evidence that the average past-due amount for customers who have been called previously about their bills is now no larger than $23.