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20 votes
20 votes
Look at the pattern shown below.

2, 4, 16, 256 ...

What is f(n+ 1) in terms of f(n), where n represents the position of a term in this pattern?

A. (F(n))^2

B. 2(f(n))

C. (F(n)-1)^2

D. 2(f(n)-1)

User Kiranr
by
3.2k points

1 Answer

22 votes
22 votes

Answer: (a)

Explanation:

Given

The pattern is 2, 4, 16, 256...

From the pattern, we can see that the next term is square of the previous i.e.


\Rightarrow 4=2^2\\\Rightarrow 16=4^2\\\Rightarrow 256=16^2
\Rightarrow 4=2^2\\\Rightarrow 16=4^2\\\Rightarrow 256=16^2

So, for the
n^(th) term, the function is
f(n)

For the next term, it is
f(n+1)

So,


\Rightarrow f(n+1)=[f(n)]^2

User MichaelsonBritt
by
3.2k points