Question

2x+3y=0
x+2y=1
solving systems by substitution

Answer 1

Answer: x=-3, y=2

Step-by-step explanation: to solve using substitution, we need either x or y by itself in one equation. let's use x from the 2nd equation since it doesn't have a constant.

so the first equation stays the same at 2x+3y=0

for the second equation, rearrange to solve for x by moving the 2y to the right -> x=2y-1

then, we can plug in this x value to x in the first equation to get,

2(2y-1)+3y=0

then solve for y,

4y-2+3y=0

4y-3y=2

y=2

then to solve for x, plug in y in either of the initial equations. lets choose the second one.

so you'd have,

x+2(2)=1

x+4=1

x=-3