Question

7. Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a

flight had 52 passengers who paid $1360, how many first class and tourist class passengers were
there?

Answer 1

40 tourist class passengers, and 12 first class passengers.

Explanation:

Here's my explanation:

We let X be the number of passengers booking for the tourist class.

If there were 52 passengers who paid 1360, then to find the number of passengers who booked first class, we write:

52-x

And if the airline fares are 30 per first class and 25 dollars for tourist class, you would say 30.00(first class)+25.00(tourist class)=1360

Using substitution, plug-in 52-x for the first class:

30(x)+25(52-x)=1360

30x+1560-25x=1360

1360-1560 =25x-30x

-200=-5x

x=40

Plug in 40 for x,

52-40=12

So, 40 tourist class passengers, and 12 first class passengers.

Answer 2

12 first class and 40 tourist

Explanation: