Question

Please someone help me with this!

A projectile is fired from the ground at an angle of 30 degrees above the horizon with an initial velocity of 960 ft/sec. If the height as a function of time t is given by h(t)=480t-16t^2, find,
The time when the projectile hits the ground
The maximum height

Answer 1

I think

h(t)=480t–16t^2

Max height is the vertex of the parabola at t = -b/2a

t = -480/-32 = 15 seconds

--> h(15)