251,258 views
27 votes
27 votes
On a given day, eight rabbits, 12 mice, and four snakes are present on the mountain range. If each animal is equally likely to be caught and consumed, what is the probability that the wolf will eat two rabbits?

User Brown Love
by
2.3k points

1 Answer

15 votes
15 votes

Answer:

7 / 69

Explanation:

Rabbit = 8

Mice = 12

Snake = 4

Total = (8 + 12 + 4) = 24

If each animal has equal probability of being caught ;

Probability of catching a rabbit ;

Number of rabbits / total number of animals

P(catching 1 rabbit) = 8 / 24 = 1/3

P(catching 2nd rabbit) :

Number of rabbits left = 8 - 1 = 7

Total number of rabbits = 24 - 1 = 23

Hence, P(catching 2nd rabbit) = 7 /23

Probability of catching two rabbits :

1 /3 * 7/ 23 = 7 / 69

User Jayesh Miruliya
by
2.7k points
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