Answer:
1.865 * 10^-4 L
Step-by-step explanation:
The equation of the reaction is:
4OH^-(aq) ----->2H2O(l) + O2(g) + 4e
Since one mole of oxygen which occupies 22.4 L is produced in the electrolysis of water by 4 Faraday of electricity as shown in the equation above;
Then;
4 * 96500 C liberates 22.4 L of oxygen
60 * 60 * 0.0200 C will liberate 60 * 60 * 0.0200 * 22.4/4 * 96500
= 1.865 * 10^-4 L