Question

12. What distance must an electron move in a uniform potential

Gradient? 200 Vcm-1 in order to gain kinetic energy 3.2x10-18 J?[3]​

Answer 1

You put it in the Spanish as a categoryI think u wanted it in Math

Answer 2

0.001m

Step-by-step explanation:

Energy=3.2×10^-18J

By conservation of energy,

energy=work done

potential gradient=E=200Vcm‐1=20000V/m

q=charge of electron=1.6×10^-19

Now,

Work done= qEd

3.2×10^-18 = 1.6×10^-19×20000×d

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solve for d

d=0.001m