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What is the exact value of sin(x/2), cos(x/2) and tan(x/2) if cos(x/6)=3/5
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User Moos
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1 Answer

5 votes

Explanation:

x/2 = 3×x/6

sin(x/2) = sin(3x/6)

cos(x/2) = cos(3x/6)

tan(x/2) = tan(3x/6) = sin(3x/6)/cos(3x/6)

looking up triple angle identities for trigonometric functions we find :

cos(3x) = 4cos³(x) - 3cos(x)

so,

cos(x/2) =

cos(3x/6) = 4cos³(x/6) - 3cos(x/6) = 4(3/5)³ - 3×3/5 =

= 4×27/125 - 9/5 = 108/125 - 9×25/125 =

= 108/125 - 225/125 = -117/125 =

= -0.936

sin(3x) = 3×sin(x) - 4×sin³(x)

so,

sin(x/2) =

sin(3×x/6) = 3×sin(x/6) - 4×sin³(x/6)

also remember,

sin²(x) + cos²(x) = 1

therefore,

sin²(x/6) + cos²(x/6) = 1

sin(x/6) = sqrt(1 - cos²(x/6)) = sqrt(1 - (3/5)²) =

= sqrt(1 - 9/25) = sqrt(25/25 - 9/25) =

= sqrt(16/25) = 4/5 = 0.8

so, again

sin(x/2) =

sin(3×x/6) = 3×sin(x/6) - 4×sin³(x/6) =

= 3×4/5 - 4×(4/5)³ =

= 12/5 - 4×64/125 = 12×25/125 - 256/125 =

= 300/125 - 256/125 = 44/125 =

= 3×0.8 - 4×0.8³ = 0.352

tan(x/2) = sin(x/2)/cos(x/2) =

= 44/125 / -117/125 = -44/117 =

= 0.352 / -0.936 =

= -0.376068376...

User Andie Hunt
by
8.2k points

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