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The distance between parallel lines 4y=3x-1 and 8y=6x-7​

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Answer: The distance between the two parallel lines is 11/12.

Explanation:

The distance between two parallel lines can be found by calculating the difference between the y-intercepts of the two lines. In this case, the y-intercept of the first line is (-1/4,0), and the y-intercept of the second line is (-7/6,0). The difference between these y-intercepts is (-1/4 - (-7/6)) = 11/12. Therefore, the distance between the two parallel lines is 11/12.

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