Question

A 2 kg ball of clay moving at 35 m/s strikes a 10 kg box initially at rest. What is the velocity of the box after the collision?

Answer 1

V = 5.83 m/s

Step-by-step explanation:

Given that,

Mass of a ball of a clay, m = 2 kg

Initial speed of the clay, u = 35 m/s

Mass of a box, m' = 10 kg

Initially, the box was at rest, u' = 0

We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.

`mu+m'u'=(m+m')V\\\\V=(mu+m'u')/((m+m'))\\\\V=(2* 35+10* 0)/(2+10)\\\\V=5.83\ m/s`

So, the velocity of the box after the collision is equal to 5.83 m/s.