Question

When you drop a 0.4 kg apple, Earth exerts a

force on it that accelerates it at 9.8 m/s
2
toward the earth’s surface. According to Newton’s third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 × 1024 kg, what
is the magnitude of the earth’s acceleration
toward the apple?
Answer in units of m/s

Answer 1

Step-by-step explanation:

a = ΣF/m

a = (0.4kg * 9.8m/s^2)/(5.98 * 10^24kg)

a = 6.56 * 10^-25 m/s^2