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What volume will 0.36 moles of carbon monoxide gas occupy at stp
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What volume will 0.36 moles of carbon monoxide gas occupy at stp

User DrupalFever
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1 Answer

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Answer: 29.4L

Step-by-step explanation:

n = m/mm

36.8g/28g/mol = 1.31mol

At STP, the molar volume is equal to 22.4L/mol, therefore, the volume that will be occupied by 36.8g carbon monoxide is:

Multiply 22.4 and 1.31,

Answer = 29.4L

User Swapnil Dalvi
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