Answer:
Approximately 2.4 x 10^-8 N.
Explanation:
The force acting on the smaller object can be calculated using the formula for gravitational force:
F = G * (m1 * m2) / d^2
Where F is the force, G is the gravitational constant (6.674 x 10^-11 N * m^2 / kg^2), m1 is the mass of the smaller object (1.5 kg), m2 is the mass of the larger object (6.0 x 10^24 kg), and d is the distance between the two objects (6.4 x 10^6 m).
Substituting these values into the formula, we get:
F = 6.674 x 10^-11 * (1.5 * 6.0 x 10^24) / (6.4 x 10^6)^2
We can simplify this expression by dividing both sides by 6.0 x 10^24 to get:
F / 6.0 x 10^24 = 6.674 x 10^-11 * (1.5 / (6.4 x 10^6)^2)
Then we can simplify the right-hand side by performing the calculations in parentheses:
F / 6.0 x 10^24 = 6.674 x 10^-11 * (1.5 / (6.4 x 10^6)^2)
= 6.674 x 10^-11 * (1.5 / 41.6 x 10^12)
= 6.674 x 10^-11 * 3.6 x 10^-13
Finally, we can multiply both sides by 6.0 x 10^24 to get the value of the force acting on the smaller object:
F = 6.0 x 10^24 * (6.674 x 10^-11 * 3.6 x 10^-13)
= 2.4 x 10^-8 N
Therefore, the size of the force acting on the smaller object is approximately 2.4 x 10^-8 N.