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Graph: y ≤ 3x + 4

A. Is (1,7) a solution? yes or no
B. Is ( 0,0) a solution? yes or no

2 Answers

2 votes

A.


7 \leqslant 3(1) + 4 \\ 7 \leqslant 3 + 4 \\ 7 \leqslant 7

B.


0 \leqslant 3(0) + 4 \\ 0 \leqslant 0 + 4 \\ 0 \leqslant 4

BOTH ARE TRUE

User Omarrrio
by
3.8k points
1 vote

Answer:

A. yes

B. yes

Explanation:

You want a graph of y ≤ 3x +4 and an indication whether (1, 7) and (0, 0) are solutions.

Graph

The graph is attached. The boundary line is solid because points on that line are in the solution set. Points in the shaded area are also in the solution set.

A. (1, 7)

This point is on the boundary line. It is a solution.

B. (0, 0)

This point is in the shaded area of the graph. It is a solution.

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Graph: y ≤ 3x + 4 A. Is (1,7) a solution? yes or no B. Is ( 0,0) a solution? yes or-example-1
User Fergus
by
4.3k points