Answer:
x = 13.6 (1 dp)
Explanation:
Using the following trig ratio to calculate the base of each triangle:
where
is the angle, O is the side opposite the angle and A is the side adjacent to the angle.
Left triangle
Given:
= 39- O = 6
- A =
![x_1](https://img.qammunity.org/2023/formulas/mathematics/high-school/xvqmvn0w56imwuw9cg0uqtojbnbpti1tai.png)
![\implies tan(39) = (6)/(x_1)](https://img.qammunity.org/2023/formulas/mathematics/college/r2xp02l8v09qk5pmirkmmx7rvk1l7vexir.png)
![\implies x_1 = (6)/(tan(39))](https://img.qammunity.org/2023/formulas/mathematics/college/d5j1r5kk54ys7cbbbsvfu21l45to8d570r.png)
Right triangle
Given:
= 44- O = 6
- A =
![x_2](https://img.qammunity.org/2023/formulas/mathematics/high-school/fyozgeygyv20u1bm0k96wwprhm1whes9v4.png)
![\implies tan(44) = (6)/(x_2)](https://img.qammunity.org/2023/formulas/mathematics/college/d49olondd0sakd8a8h1f7zmo37093kdj3l.png)
![\implies x_2 = (6)/(tan(44))](https://img.qammunity.org/2023/formulas/mathematics/college/46ewtdvsc3lmfiftefw77m8m1hj0p3qmai.png)
Length of x
![x = x_1+x_2](https://img.qammunity.org/2023/formulas/mathematics/college/5o3oajv8e2m664s46sfyw50wktrv09y03t.png)
![\implies x=(6)/(tan(39))+(6)/(tan(44))](https://img.qammunity.org/2023/formulas/mathematics/college/2y47j6y15bqhrlziq4r5aep9chy6jwiffq.png)
(1 dp)