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(1+tan^2x)cot^2x=csc^2x prove the identity

User Aulana
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1 Answer

4 votes

To prove this identity, we can start by multiplying both sides of the equation by cot^2(x) to get rid of the cot^2(x) on the left-hand side:

(1+tan^2(x))cot^2(x) = csc^2(x) * cot^2(x)

1 + tan^2(x) * cot^2(x) = csc^2(x) * cot^2(x)

Next, we can use the identity cot^2(x) = csc^2(x) - 1 to simplify the left-hand side:

1 + (tan^2(x) * cot^2(x)) = csc^2(x) * cot^2(x)

1 + (tan^2(x) * (csc^2(x) - 1)) = csc^2(x) * (csc^2(x) - 1)

We can simplify the right-hand side by multiplying the two factors in the parentheses:

1 + (tan^2(x) * (csc^2(x) - 1)) = (csc^2(x))^2 - csc^2(x)

Now we can use the identity tan^2(x) = 1 / csc^2(x) to simplify the left-hand side:

1 + (1/csc^2(x) * (csc^2(x) - 1)) = (csc^2(x))^2 - csc^2(x)

1 + (1 - 1/csc^2(x)) = (csc^2(x))^2 - csc^2(x)

Next, we can combine like terms on both sides of the equation to get:

1 = (csc^2(x))^2 - csc^2(x)

1 = csc^4(x) - csc^2(x)

Finally, we can add csc^2(x) to both sides to get:

1 + csc^2(x) = csc^4(x)

csc^2(x) = csc^4(x) - 1

This is the same as the original equation, so we have proven that the identity is true.

User Yovav
by
7.0k points
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