Question

Joe pushes down the length of the handle of a 12.9 kg lawn spreader. The handle makes an angle of 41.7◦ with the horizontal. Joe wishes to accelerate the spreader from rest to 1.39 m/s in 1.7 s. What force must Joe apply to the handle? Answer in units of N.

Answer 1

Below

Step-by-step explanation:

Only the HORIZONTAL force , F cos 41.7 moves the spreader forward

The acceleration = change in V / change in t = 1.39/1.7 = .818 m/s^2

F = m * a

F cos 41.7 = 12.9 * .818 shows F = 14.12 N