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Algebra HELP PLS

The ceiling of Victoria's living room is a square that is 15√2 ft long on each side. To decorate for a party, she plans to hang crepe paper around the perimeter of the ceiling and then from each corner to the opposite corner. Victoria can buy rolls that each contain 30 ft of crepe paper. what is the minimum number of rolls she should buy?

pls show your work

User Alancc
by
5.4k points

1 Answer

6 votes

Answer:

  • Minimum 5 rolls

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Total length we need is the sum of the perimeter and two diagonals of the square.

Perimeter:

  • P = 4s
  • P = 4(15√2) = 60√2 ≈ 85 ft (rounded up to the whole number)

Diagonals:

  • 2d = 2s√2 = 2(15√2)(√2) = 30*2 = 60 ft

Total length:

  • 85 + 60 = 145 ft

Number of rolls:

  • 145/30 ≈ 5 (rounded up to the whole number)
User Nerowolfe
by
5.9k points
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