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A rubber ball is dropped from an initial height of 40 feet. The ball consistently rebounds to 80% of its previous height

1 Answer

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Answer:

The ball travels (exactly) 75 feet.

Explanation:

Assuming the balls comes to rest:

S = a1 / (1 - r)

Now a1 is the first bounce, 20 ft (10 feet up, 10 feet down.

r is 2/3

S = 20 (1 / (1 - 2/3)

S = 20 / (1/3)

S = 60

Yet that is only the bounce. The drop of 15 feet must be added.

User Mike Koder
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