Answer:
1.82 x 10^-12 m.
Step-by-step explanation:
The de Broglie wavelength of an electron traveling at 1.02 x 10^5 m/s is 1.82 x 10^-12 m.
The de Broglie wavelength of a particle is a measure of the particle's wave-like behavior, and it is given by the following equation:
λ = h / mv
where λ is the de Broglie wavelength, h is the Planck constant, m is the mass of the particle, and v is the velocity of the particle.
In the case of an electron traveling at 1.02 x 10^5 m/s, the de Broglie wavelength is given by the following calculation:
λ = 6.62 x 10^-34 J * s / (9.11 x 10^-31 kg * 1.02 x 10^5 m/s)
This simplifies to:
λ = 1.82 x 10^-12 m
Therefore, the de Broglie wavelength of an electron traveling at 1.02 x 10^5 m/s is 1.82 x 10^-12 m.