Question

An electronics store receives a shipment of 30 graphing​ calculators, including 7 that are defective. Four of the calculators are selected to be sent to a local high school. How many of these selections will contain no defective​ calculators?

Answer 1

The number of ways to select 4 calculators with no defective ones is C(23, 4) = 8,235.

Step-by-step explanation:

To calculate the number of selections that will contain no defective calculators, we need to use the concept of combinations.

The total number of ways to select 4 calculators from a pool of 30 is given by the formula C(30, 4) or 30 choose 4, which is equal to 27,405.

Now, the number of ways to select 4 calculators with no defective ones is given by C(23, 4) or 23 choose 4, which is equal to 8,235.

Therefore, there are 8,235 selections that will contain no defective calculators.