Question

The orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m.

The tangential speed of the satellite is
m/s. (Round to the nearest whole number, do not add any punctuation.)

Answer 1

V=d/t
V - velocity
d - distance
t - time

V=C/T
(C - circumference
T - period)
Since it is a circular motion, we should take this values, which are equivalent

V=2*pi*R/T= 2*3.14*(4*1010)/(2*107)=119